If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+6x-56=0
a = 5; b = 6; c = -56;
Δ = b2-4ac
Δ = 62-4·5·(-56)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-34}{2*5}=\frac{-40}{10} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+34}{2*5}=\frac{28}{10} =2+4/5 $
| 3m^2+2m+7=0 | | x-55=77 | | 2(t-2)+9=-13 | | 15x-2=0 | | f(1)=6/2*1-3 | | -9(3a-15)=0 | | 6x^2-72x-798=0 | | -27=3(2x+1) | | 1/6d=52 | | -27=3(2x+1 | | f(1)=6/2(1)-3 | | 3v=-25 | | 9x-3/x=3 | | 2t²-7t-49=0 | | 3.22x+28.98=57.96 | | (5x^2+6x-4)=0 | | 11x^2-16x-91=0 | | (5x^2+6x+4)=0 | | K²-4k-45=0 | | (5x^2+6x)^(1/3)=2 | | 15+2×2-15=x | | 7(5x-3)=4x-12 | | -5(6x-7)+4=-30x+39 | | (V^2)+3v=-2 | | 2(x+4)+4=-6 | | -37x^2+-232x+-720=0 | | 2+(3-2x)=19 | | |f−6|=|f+8| | | −3(-5)+7y=5(-5)+2y | | 6x+7=8x−156x+7=8x-1 | | 18-3x=5(x-2) | | -5(2t-2)+4t=5t-7 |